
In 1993, Moose Population: 3280
In 1999, population became: 4960
P (Population) , t (years)
t = 6 —> 4960 - 3280 = 1680
Average Change —> 1680/6 = 280 moose/year
• In terms of 1990:
t = 3 —> 3280-3 (280)
P(1990) = 2440
P(t) = 2440 + 280t
• In 2003; t = 13
P(13) = 2440 + 280 (13)
P(13) = 2440 + 3640
P(13) = 6080
• Moose population in 2003
= 6080
Answer:
1.15
Step-by-step explanation:
20.7 divided by 18 equals 1.15
Answer:
In the time(x) column add 3 every time (start with 3 in first column). For the steps (y) add 126 every time (start with 126 in first column.
Step-by-step explanation:
They could be rational, irrational, whole, or an integer.
Answer:
4)
Step-by-step explanation:hope this helps