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2 years ago

On a map 1/4 inch = 50 miles. If two cities appear 3 inches apart, how many

Mathematics

1 answer:

Mumz [18]2 years ago

4 0

Answer:

Step-by-step explanation:

3⅛ inches × (50 miles)/(¼ inch) = 625 miles

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

P: 2,012

OleMash [197]

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

Para aprender más sobre volúmenes: brainly.com/question/23940577

#SPJ1

3 0

1 year ago

What percent of all patients are blood type AB? Round your answer to the nearest tenth of a percent. Type a numerical answer in

Makovka662 [10]

Depends on the type of AB, is it AB positive or AB negative

AB-positive: 3.4 percent
AB-negative: 0.6 percent

if you need both add the percentages together

6 0

2 years ago

What is the unit rate for 3 boxes for $5

Andreas93 [3]

I think the answer to your question is
3
/
5

6 0

2 years ago

4 5/6+3/5= my daughter is needing help she's in the 5th grade

V125BC [204]

Answer:5 13/30

Step-by-step explanation:

4+5/6 + 3/5

5/6 +3/5

Find LCD of 5/6 and 3/5

25/30 + 18/30

43/30= 1 13/30

4+1+13/30= 5 13/30

7 0

2 years ago

Read 2 more answers