(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
First bring the 9 to the other side by subtracting it so you get the equation; x^2+10x-9=0 and you answer would be x=9 and x=1. you may have wrote the question own wrong? is the x^2 negative? if so i give my answer :)
Answer: OPTION C
Step-by-step explanation:
You can solve the problem shown above keeping on mind the facts shown below:
As you can see in the graph attached in the problem, there is a hole in the function at x=6.
By definition, this indicates that the function shown is not continuous at that point.
Therefore, you can conclude that the value in which is the graph discontinuous is the value of the option c: 6
Answer:
47/30
Step-by-step explanation:
Answer:
steps below
Step-by-step explanation:
1. The series contains a combination of two arithmetic sequence series. The number series in the odd position (100,90,80,..) is an arithmetic series with a common difference of 10, and the even number group (3,10,15,...) is another arithmetic series with a common difference of 5.
2. sequence 1 (Odd): a₁ = 100 d = 10 next term is 60
sequence 2 (Even): a₁ = 5 d = 5 next term is 20
3. next 2 terms of the series are 60, 20
