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DiKsa [7]
3 years ago
10

in the diagram below P(x:y)is a point in the third quadrant. ROP=B and 17 cos B is equal to -15 calculate the values of x and y

and r ​
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

you showed no diagram or any picture / screenshot

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HELP PLEASE!!!!! ASAP
Lostsunrise [7]

Answer:

Step-by-step explanation:

I hope this helps!

1. You would see how many parts there are.

2. See how many are filled in.

3. And see how many remain.

4. Now that you have numbers to match the chart, see what numbers match in the answer key.

5. Complete! Now you have your answer!

P.S. I hope this helps!

7 0
4 years ago
Read 2 more answers
PLS HELP ME QUICK.GRAPH INCLUDED
ahrayia [7]

Answer:

C ) translate ∠MRS down and to the right

Step-by-step explanation:

MN and JK are parallel and are intersected by line QT.

Since MN and JK are parallel and are intersected by line QT So, ∠MRS and ∠JST are corresponding angles

So, ∠MRS = ∠JST (Corresponding angles are equal)

Now transformation could be used to show that ∠MRS is congruent to ∠JST

So, Wee need to translate  ∠MRS down and to the right

Then it will overlap ∠JST

So, Option C is true .

6 0
3 years ago
Find all the roots of the equation x^4-4x^3+x^2+12x-12=0
inysia [295]
Hi there!
The question here asks us to find all the roots, or solutions, of the quartic equation x⁴ - 4x³ + x² + 12x - 12 = 0. We can start off by using the Rational Root Theorem, which calls for the constant over the leading coefficient, which for us would be 12 over 1. Since we need to list all the factors of 12, they all become + or -. 
<u>+</u>12 / <u>+</u> 1
=> <u>+</u>1, <u>+</u>2, <u>+</u>3, <u>+</u>4, <u>+</u>6, <u>+</u>12 / <u>+</u>1
Now, just simplify each one. We get the possible roots 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12. The next part is the most tedious. Plug in each possible factor for x and see if the resulting value is 0. We get that only root 2 makes the whole equation equal to zero. However, we are not done yet. The question asks for the ALL the roots of the equation, not just real, but also imaginary. Let's use synthetic division to find the other roots. 
We can set the divisor to 2, as (x - 2) = 0 is equal to x = 2. 
2| 1 -4 1 12 -12
       2 -4 -6 12
    1 -2 -3 6  0
We can now factor the whole original equation to (x - 2)(x³ - 2x² -3x + 6) = 0. Now, we have to factor the expression x³ - 2x² -3x + 6, and grouping seems like the most appropriate way.
x³ - 2x² -3x + 6 = 0
(x³ - 2x²) + (-3x + 6) = 0
x²(x - 2) - 3(x - 2) = 0
(x² - 3)(x - 2) = 0
Next, use the Zero Product Property to get the values of x.
x² - 3 = 0
x² = 3
x = √3
x ≈ <u>+</u> 1.73
x - 2 = 0
x = 2
Therefore, the roots of the equation x⁴ - 4x³ + x² + 12x - 12 = 0 are x = 2,x = 2 (repeated solution), x = 1.73, x = -1.73. Hope this helped and have a great day!

3 0
3 years ago
827774 x 86567 x 87893087 x 878904 x 8907389 x 0 x 7890 x 7893 see if you can answer that nice job if u did
djverab [1.8K]

Answer:

hm

Step-by-step explanation:

5 0
3 years ago
Triangle ABC has the following vertices:
guajiro [1.7K]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
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