<span>
The good answer is 9
(9:9=1 and 27:9=3)</span>
If the parent graph f(x) = x² is changed to f(x) = 2x², the vertex of the parabola will still remain (0, 0) because whenever the equation of a parabola is in the form y = ax², the vertex will always be (0, 0).
Now if <em>a</em> is a big number, the parabola will become narrower.
So it will stretch vertically and become narrower.
<span>Given the diagram, where AB and EF are horizontal lines and CB is a vertical line segment.
Given that FB : FC = 4 : 3,
From the diagram, the coordinate of A is (-10, -8) and the coordinate of C is (-3. -1).
We can also see that the coordinate of B is (-3, -8) (since CB is a vertical line means that B is the same x-value as C and AB is a horizontal line means that B is the same y-value as A)
Recall that the coordinate of a point dividing a line segment in the ratio m:n is given by (x1 + m/(m+n) (x2 - x1), y1 + m/(m+n) (y2 - y1))
Thus, since FB : FC = 4 : 3, this means that point F divides the line segment BC in the ratio 4 : 3.
Thus, the coordinate of F is given by (-3 + 4/(4+3) (-3 - (-3)), -8 + 4/(4+3) (-1 - (-8))) = (-3 + 4/7 (0), -8 + 4/7 (7)) = (-3, -4).
Also, given that FB : FC = 4 : 3, this means that point D divides the line segment AC in the ratio 4 : 3.
Thus, the coordinate of D is given by (-10 + 4/(4+3) (-3 - (-10)), -8 + 4/(4+3) (-1 - (-8))) = (-10 + 4/7 (7), -8 + 4/7 (7)) = (-6, -4).
Therefore, the coordinates of point D is (-6, -4).</span>
3*10⁻⁵ + 0.0000022
= 0.00003 + 0.0000022 = 0.0000322
= <span>0.0000322 = 3.22 * 10</span>⁻⁵
