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scZoUnD [109]
3 years ago
15

Given constants a and b such that x2 + ax + b has factors (x + 7) and (x + 2) what is a?​

Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

a=9 , b=14

Step-by-step explanation:

Just do the operation (x+7)(x+2)

x(x)+x(2)+7(x)+7(2)

x^2+2x+7x+14

x^2+9x+14

So a=9 and b=14

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Yes it's possible you just got to crop it to your liking

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The purchase price of a car is $22,500.00 and the 5 year loan has a 10% down payment and an annual interest rate of 6.75%. What
kozerog [31]

Answer:

$398.59

Step-by-step explanation:

7 0
3 years ago
OK SO HERES THE PROBLEM. MY BRAIN HURTS. PLZZZ help me with this math problem
jeka57 [31]

Oh Foxy, Foxy, how totally debilitated you must be !  Try to relax.  Nobody
enjoys a painful brain, and believe me, this problem is not worth it.

Let me put it to you this way:  What if the problem said . . .

-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?

If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .

That's <em>almost </em>exactly what the problem <em>does</em> say. 
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.

Surely you can handle it from here, even with half of your brain
tied behind your back.

Take a good hard look at ' A ', and then go lie down.


7 0
3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0
3 years ago
Follow this link to view Juan's work. Critique Juan's work by justifying correct solutions and by explaining any errors he made
Aleksandr [31]

Answer:

I don't no sorry please bro sorry

4 0
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