Answer:
25 dimes & 12 nickels
Step-by-step explanation:
Let there be "n" nickels and "d" dimes
Total, there are 37 of them, so we can write:
n + d = 37
Also, valueof nickel is 0.05 and value of dime is 0.10 (in dollars) and total value of these 37 coins is 3.10, so we can write:
0.05n + 0.10d = 3.10
Now we can write first equation as:
n + d = 37
n = 37 - d
Replace this into equation 2 and solve for d:
0.05n + 0.10d = 3.10
0.05(37 - d) + 0.10d = 3.10
1.85 - 0.05d + 0.10d = 3.10
0.05d = 3.10 - 1.85
0.05d = 1.25
d = 1.25/0.05
d = 25
Now, n = 37 - d, n = 37 - 25 = 12
So,
There are 25 dimes & 12 nickels
It is called a point of concurrency
Answer: B
If you multiply equation 1 by -5 you get: -10x-y=3.
If you multiply equation 2 by 2 you get: 10x+4y=14
Add the systems together to eliminate x.
Answer:
- equation: d(h) = 0.25|h -1600| -400
- depth is 250 ft at 1000 ft and 2200 ft from the west edge
Step-by-step explanation:
The crater shape can be modeled by an absolute value function with a slope of 0.25. The vertex of the function will not be at (0, 0) but will be at (1600, -400). The usual methods of translating functions apply. Horizontal displacement of the vertex is subtracted from the independent variable; vertical displacement is added to the function value.
d(h) = 0.25×|h -1600| -400
We know the horizontal displacement is 1600 ft, because the depth changes at a rate of 1/4 foot for each horizontal foot. A depth change of 400 feet will require 1600 horizontal feet to accomplish.
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At a depth of 250 ft, the distance from the west edge can be found from ...
-250 = 0.25|h -1600| -400
150 = 0.25|h -1600| . . . . . . . . add 400
600 = |h -1600| . . . . . . . . . . . multiply by 4
This resolves to two equations:
- -600 = h -1600 ⇒ h = 1000
- 600 = h -1600 ⇒ h = 2200
The depth is 250 ft at distances of 1000 ft and 2200 ft from the west edge.
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<em>Comment on the equation</em>
We have chosen to make depths be negative numbers. If you want the equation to give positive numbers for depth, multiply it by -1:
d = 400 -0.25×|h -1600|