Answer:
Step-by-step explanation:
G(f(2+x))=g(2+x)^2+3(2+x)=2(2+x)^2+3(2+x)-2=2(4+4x+x^2)+6+3x=8+8x+2x^2+6+3x=2x^2+11x+14
<span>Let x=apples that Andre picks
Then x/3=apples that Maria picks
And 2x=apples that Jane picks
Soooo,
x +(x/3)+2x=840 multiply each term by 3
3x+x+6x=2520 collect like terms
10x=2520
x=252</span>
Y=2x-6 (4, 3)
(X, Y)
3=2(4)+b
3=8+b
-5=b
Y=2x-5
Answer:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
-------------------------
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.
Y + 4 = -4 (x - 6) ...point slope equation form
hope it helps
