12
Step-by-step explanation:
12 i think so because i did it before
Answer:
Return trip travel time: 7h
Step-by-step explanation:
Let d be the distance.
Index 1 refers to initial trip, index 2 refers to the return trip.
v1=70mi/h
v2=40mi/h
t2=t1+3h, or t1=t2-3h (travel times)
d=v1×t1=v2×t2
v1×(t2-3)=v2×t2
v1 t2 -3 v1=v2 t2
v1 t2 - v2 t2=3 v1
t2(v1-v2)=3v1
t2=3v1/(v1-v2)
Or
t2=3×70/(70-40)=3×70/30=7h
24 / 4 = 6
6 x 9 = 54
there will be 54 catfish
(2x-3)(5x+9)
2x*5x-3*9
10x-27
The total distance between the airplane and the runway is 14102 ft.
The total height distance between the airplane and the runway can be solved through the equation:
14,080 ft + 22ft = <span>
14102 ft</span>Since the runway is below sea level, it adds to the total distance.
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