Answer:
11 $
Step-by-step explanation:
substitute 12 into t
making (0.5 × 12) + 5 = 6 + 5 = 11 $
Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
Answer:
x ∈ (-∞, 3) U (6, ∞).
Step-by-step explanation:
We use factorization and optain
Then, we have two critical points: x=3 and x=6. Now:
(i) for x < 3 we have that x-6 <0 and x-3 <0. Then (x-6)(x-3) > 0.
(ii) for 3 < x < 6 we have that x -6 <0 and x -3 > 0. Then (x-6)(x-3) < 0.
(iii) for x > 6 we have that x-6 >0 and x-3 > 0. Then, (x-6)(x-3) > 0.
conditions (i) and (iii) satisfy the inequatliy, then the solution is x ∈ (-∞, 3) U (6, ∞).
The graph is in the picture below.
Answer:
The range would you expect 99.00 percent of the grades is 44.2 to 95.8
Step-by-step explanation:
In order to calculate the range would you expect 99.00 percent of the grades we would have to make the following calculation:
range would you expect 99.00 percent of the grades=mean ± 2.58* standard deviation
According to the given data we have the following:
mean=70
standard deviation=10
Therefore, range would you expect 99.00 percent of the grades= 70± 2.58*10
=70 - 2.58*10 to 70 + 2.58*10
Therefore, range would you expect 99.00 percent of the grades=44.2 to 95.8.
The First one is the answer.