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GenaCL600 [577]
2 years ago
10

PLEASE HELP ASAP Will MAKE BRAINLIST

Mathematics
1 answer:
WINSTONCH [101]2 years ago
6 0

Answer:

The second answer is correct

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A sales associate in a department store earns a commission on each suit and each pair of shoes sold. One week, she earned $47 in
earnstyle [38]
3s + h = $47
7s + 2h= $107


3s + h =$47
3s - 3s + h = $47 -3s
h = $47 - 3s

7s + 2($47 - 3s) = $107
7s + 94 -6s = 107
s + 94 = 107
s +94 -94 = 107- 94
s = 13

3(13) + h = $47
39 + h =$47
39 -39 + h= $47-39
h = 8

Check
7s + 2h= $107
7(13) + 2(8)= $107
91 + 16= 107
107 = 107

She earns $13 per suit sold and $8 per pair of shoes sold.



5 0
3 years ago
(8y²+2)+(5-3y²) onojnonl
LekaFEV [45]

Answer:

5y^2 +7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the area of the side of this house?
melamori03 [73]

Answer:

25

Step-by-step explanation:

8 0
3 years ago
5 Exam-style ABCD is a kite.
Mnenie [13.5K]

let's recall that in a Kite the diagonals meet each other at 90° angles, Check the picture below, so we're looking for the equation of a line that's perpendicular to BD and that passes through (-1 , 3).

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of BD

y = \stackrel{\stackrel{m}{\downarrow }}{3}x-1\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line whose slope is -1/3 and passes through point A

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-1)}]\implies y-3=-\cfrac{1}{3}(x+1) \\\\\\ y-3=-\cfrac{1}{3}x-\cfrac{1}{3}\implies y=-\cfrac{1}{3}x-\cfrac{1}{3}+3\implies y=-\cfrac{1}{3}x+\cfrac{8}{3}

5 0
3 years ago
-3 1/6 + 2 7/9 + 5 2/3 estimated
adelina 88 [10]

Answer:

5.28 if you round to the nearest hundredth. Drop a best answer and a like if it helped

3 0
3 years ago
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