Hi,
Let Sydney's age be x.
Devaughn=(x-15)
x+(x-15)=37
x+x-15=37
2x-15=37
2x=37+15
2x=52
x=52/2
x=26
Sydney is 26 years old.
Hope this Helps you.
Answer:
B. f(x) = -x + 11
Step-by-step explanation:
First if you rearrange the equation you get f(x) = -x + 11, like this:
x + y = 11
Minus x from both sides
y = -x + 11
F(x) and y are interchangeable so we just put f(x) in
f(x) = -x + 11
Each of the graphs are attached and we see that they are the same!
<em>Hope this helps!!</em>
<em>- Kay</em>
Answer:
0.0274
Step-by-step explanation:
The mean is 
and the standard deviation is 
Calculate
for 
If 
then 
and
Use table for normal distribution probabilities to get that
Please don't ask 2 questions in 1 question
remember that percent is parts out of 100 so x%=x/100
basically just remove the percent sign and move the decimal place 2 places to the left to convert to fraction
the first one
20 dollars
4.75% tax
15% tip
it depends if you want to tip on the total with tax or without tax
it is better to top on the without-tax value since tax comes from you so
find 4.75% of 20 and add that to 15% of 20 then add that to 20 to get the proper value
scenarios
1. 20+(20 times 4.75%)+(20 times 15%)=23.95
2. ([(20 times 104.75%)] times 115%)=24.09
both are bellow $25 so $25 shoudl be enough to cover it
total cost of a spa treatment of 42 with 6% tax and 20% tip
so you could again do two things:
1. apply tax and give tip on the new amount
2. find the tip and add that to the tax of only 42
scenarios:
1.(42 times 106%) times 120%=$50.4
2. (42 times 20%) +(42 times 106%)=$52.92
it depens on what you tip on
Answer:
Final answer is ![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
.
Step-by-step explanation:
Given problem is ![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
.
Now we need to simplify this problem.
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
Hence final answer is .
