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Crazy boy [7]
4 years ago
12

An 8.5-meter ladder is leaning against a vertical wall. How many meters is its base from the wall if the ladder reaches 7.5 mete

rs up the wall?
Mathematics
1 answer:
Monica [59]4 years ago
7 0

Answer:

  4 m

Step-by-step explanation:

The geometry is that of a right triangle with hypotenuse 8.5 m and one side of length 7.5 m. If "b" represents the distance from the base of the ladder to the wall, the Pythagorean theorem tells us ...

  b² + 7.5² = 8.5²

  b² + 56.25 = 72.25

  b² = 16 . . . . . . . . . . . . . subtract 56.25

  b = 4 . . . . meters . . . (take the square root)

The base of the ladder is 4 m from the wall.

_____

You may recognize this as the 8-15-17 Pythagorean triple, scaled by 1/2.

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There are 256 ways in total.

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The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

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Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

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According to the definition of combination: \binom{n}{r}=\frac{n!}{r!(n-r)!}

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Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: \binom{8}{3}=\frac{8!}{3!(5)!}=56

For 4 heads: \binom{8}{4}=\frac{8!}{4!(4)!}=70

For 5 heads: \binom{8}{5}=\frac{8!}{5!(3)!}=56

For 6 heads: \binom{8}{6}=\frac{8!}{6!(2)!}=28

For 7 heads: \binom{8}{7}=\frac{8!}{7!(1)!}=8

For 8 heads: \binom{8}{8}=1

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

\binom{8}{4}=\frac{8!}{4!(4)!}=70

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