Line segment AD is 4cm. Because A is the center, any lines coming off the centerpoint are congruent. So if line AC is 4cm, then line AD has to be 4cm as well.
Step-by-step explanation:
Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC
To prove = ∠3= 49°
Solution:
In figure, m∥n cut by traversal t.
So, ∠DEF = ∠ABC(alternative exterior angles)
∠1 + ∠2 = ∠4 + ∠5
∠ABC = ∠1 + ∠2 = 50° + 48° = 98°
Also given that s bisect angles ∠ABC.
∠4 = ∠5
∠ABC = ∠4 + ∠5 = 98°
∠4 + ∠4 = 98°
2∠4 = 98°
∠4 = 49°
∠4= ∠3 = 49° (vertically opposite angles)
∠3 = 49° ,hence proved
Answer:
1.5m
Step-by-step explanation:
A hexagon has 6 sides,
so divide 6 by 9.0m
you get 1.5m
u( t - 2s)
double s is expressed as 2s
subtract this result from t gives t - 2s
multiply this result by u gives u × (t - 2s) = u( t - 2s)
Answer:
Domain: all real numbers
Range: all real numbers
Step-by-step explanation:
I'm assuming you mean the function
. That's usually written
f(x) = x^(1/5) with the ^ meaning "to the power of..." and the fraction exponent in parentheses so as not to be confused with x^1/5 which could mean x to the first power, divided by 5.
Fractional exponents are used to indicate roots. In this case, x is being raised to the 1/5 power, so this is the fifth root of x, written
. The 5 is called the root index.
For odd roots, like this one, the domain is all real numbers--<em>x</em> can be any number at all. So the domain is all real numbers.
The range is also all real numbers. Attached is a graph of this function. It might not look like it, but the graph rises to the right to any height. The larger <em>x</em> gets, the larger the 5th root gets. A similar thing happens on the left--the smaller <em>x</em> gets, the smaller the 5th root gets.
EDIT: see the comment. For the function
, the domain is all real numbers. The range is positive real numbers. I'll attach a graph!