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Sedbober [7]
3 years ago
14

Find the values of x and y

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

x = 11

y = 70°

Step-by-step explanation:

x + 2 = 13

The lines on each side are corresponding.

11 + 2 = 13

Y is corresponding with the 70° corner.

That means the corresponding corner (y) is also 70°.

julsineya [31]3 years ago
4 0

Answer:

y = 70 degrees

x = 11

Step-by-step explanation:

The side opposite x + 2 is equivalent so they will both be equal to 13.

To get the meaning of x, simply subtract 2 from 13 giving you x = 11.

Y is across from corner C, which is 70 degrees. These angles are equivalent to each other, meaning that angle y is also 70 degrees.

Hope this helps you :)

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Max and Sharifa are both saving to buy the same model of DVD player, which costs $99, including tax. Max already has $31.00 and
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Answer:

Sharifa can pay for the DVD player first.

Step-by-step explanation:

<u>Max:</u>

99 - 31 = $68 remaining

68 / 8.5 = <em>8 weeks</em>

<u>Sharifa:</u>

99 - 25.5 = $73.50 remaining

73.5 / 10.5 = <em>7 weeks</em>

7 0
3 years ago
Find the values of x and y.
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y=180-63-63/2=27degree...in triangle mln

x=180-27-63=90....in triangle mon

6 0
2 years ago
Read 2 more answers
What is log6 8+ log6 27
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\log_6 8 + \log_6 27=\log_6 (8 \times 27)=\log_6 216=3
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2 years ago
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As a salesperson, you are paid $50 per week plus $2 per sale. This week you
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Answer:25 sales

Step-by-step explanation:

$100 is how much you want to make.

you automatically make $50

100-50=50

if you make $2 per sale then you make the equation 50/2=?

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5 0
3 years ago
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A study of 4,430 U.S. adults found that 2,913 were obese or overweight. The 95% confidence interval for the proportion of adults
IrinaK [193]

Answer:

0.658 - 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.644

0.658 + 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.672

We are 95% confident that the true proportion of adults overweight is between 0.644 and 0.672

Step-by-step explanation:

We can begin founding the estimated proportion of people overweight:

\hat p =\frac{2913}{4430}= 0.658

We need to find a critical value for the confidence level using the normal standard distribution. We know that 95% is the confidence level, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the true population proportion of interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the data provided we got:

0.658 - 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.644

0.658 + 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.672

We are 95% confident that the true proportion of adults overweight is between 0.644 and 0.672

6 0
2 years ago
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