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posledela
3 years ago
7

two lines intersect.One has gradient 4 and y-axis intercept 3. The other has gradient 6 and cuts the y-axis at (0,1). What is th

e point of interesection of the lines?​
Mathematics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

(1, 7 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Then the equations of the 2 lines are

y = 4x + 3 → (1)

y = 6x + 1 → (2)

Substitute y = 6x + 1 into (1)

6x + 1 = 4x + 3 ( subtract 4x from both sides )

2x + 1 = 3 ( subtract 1 from both sides )

2x = 2 ( divide both sides by 2 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting into (1)

y = 4(1) + 3 = 4 + 3 = 7

Point of intersection = (1, 7 )

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A student's pay of $18 an hour is $4 more than twice the amount the student earns per hour at an internship. Enter and solve an
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1. You have that a<span> student's pay of $18 an hour </span>is <span>$4 more than twice the amount the student earns per hour at an internship.

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 3. When you clear the variable "x", you obtain:

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svet-max [94.6K]

Here we will use the trial and error method.

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<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
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