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Dmitrij [34]
3 years ago
9

What are 3 different equations that have x=5 as a solution

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

1) x+y=50

2) 5x+2y=200

3)2x+4y=200

Hope this helps!

IRINA_888 [86]3 years ago
3 0

Answer:

x+3=8, 2x-8=2, and 4x-4=16

Step-by-step explanation:

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Prettyy pretty help :):) ?
Nitella [24]

Answer: B

Step-by-step explanation:

5 0
3 years ago
A man went on a camping and hiking trip over fall break after two full days 3/10 of his supplies were gone. How many days could
Sergeeva-Olga [200]
Tasha mack I don’t know this
5 0
3 years ago
A man earned $180 for working 14 hours. How many hours must he work to earn 300
RideAnS [48]

Answer:

it would be roughly 24 hours

Step-by-step explanation:

180÷14

12.8571428571

simplify to 12.85

12.85× X = 300

X=24

8 0
3 years ago
The cost to rent a moving van is $23 plus as a additional $7 per hour. For $37, what is the maximum amount of time that a moving
lapo4ka [179]

Given:

Fixed cost to rent a moving van = $23

Additional cost = $7 per hour.

To find:

For $37, the maximum amount of time that a moving van can be rented for.

Solution:

Let the moving van be rented of t hours.

Total cost = Fixed cost + Additional cost

\text{Total cost}=23+7t

For $37, the total cost should be less than 37.

23+7t\leq 37

7t\leq 37-23

7t\leq 14

Divide both sides by 2.

t\leq 2

Since maximum value of t is 2, therefore the moving van can be rented for maximum 2 hours.

5 0
3 years ago
A store has been selling 300 DVD burners sold per week at 350 each. A market survey indicates that for each $ 30 rebate offered
Nana76 [90]

Answer:

3 times rebate will maximize its revenue

Step-by-step explanation:

Given that a store has been selling 300 DVD burners sold per week at 350 each

A market survey indicates that for each $ 30 rebate offered to buyers, the number of units sold will increase by 60 a week.

If x times rebate is offered then units sold would be 300+60x

Thus original revenue= 300*350 = 105000

After rebate of x times 30 dollars we have

New revenue

R(x) = (300+60x)(350-30x)\\= 105000+12000x-1800x^2\\R'(x) = 12000-3600x\\\\R"(x) = -3600

Equate first derivative to 0 to get

x=\frac{12000}{3600} =3.333

i.e. 3 times rebate will maximize its revenue

3 0
3 years ago
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