Answer:
<u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
Step-by-step explanation:
Given :
- f(x) = x³ + 3
- g(x) = 2x² + x - 1
Finding (f × g)(x) :
- f(x) × g(x)
- (x³ + 3)(2x² + x - 1)
- 2x⁵ + 6x² + x⁴ + 3x - x³ - 3
- <u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
Answer:
C.
Step-by-step explanation:
-3 7/8 rounds down to -4
4.63 rounds up to 5
-4 x 6 + 5
-24 + 5
-19
her answer (-19.14) also rounds to -19
So yes, it is reasonable and the correct response is C.
Answer:
The quotient is the solution to a division sum.
Step-by-step explanation:
A single number can not have a quotient.
Answer:k=0.67
Step-by-step explanation:
Answer:
B: 11 minutes.
Step-by-step explanation:
So, we know that the machine prints at a constant rate.
After 3 minutes, the machine prints 108 posters.
So, let’s find the <em>unit rate. </em>We will divide the output over the input. So:
![108\text{ posters}/3\text{ minutes}=36\text{ posters/min}](https://tex.z-dn.net/?f=108%5Ctext%7B%20posters%7D%2F3%5Ctext%7B%20minutes%7D%3D36%5Ctext%7B%20posters%2Fmin%7D)
So, the unit rate of the machine is 36 posters per minute.
We can write an equation. If t represent the number of minutes and p represent the amount of posters, then:
![p=36t](https://tex.z-dn.net/?f=p%3D36t)
Gives the amount of posters p and t minutes.
We want to know how long it will take Jeffrey to make 396 posters.
So, we can substitute 396 for p and solve for t. Hence:
![396=36t](https://tex.z-dn.net/?f=396%3D36t)
Divide both sides by 36:
![t=11](https://tex.z-dn.net/?f=t%3D11)
Therefore, it will take Jeffrey 11 minutes to make 396 posters.