She spends $50.86.
Cost for 1 yard of fabric is $8.98.
So to find the the cost of 5 yards of fabric, multiply $8.98 x 5 = $44.9. Therefore for the 5 yards of fabric she paid $44.9.
To find how much she paid for 2 spools of thread subtract the amount she spent at the craft store and the cost for the 5 yards of fabric.
&50.86 - $44.9 = $5.96.
Therefore the cost of 2 spool of thread is $5.96 / 2 = $2.98
Therefore the cost of 1 spool of thread is $2.98.
To check if it’s correct just add the cost of the 5 yards of fabric and the 2 spools of thread.
$44.9 + $5.96 = $50.86
Answer:
34
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ 1, 6 ], thus
f(b) = f(6) = 6³ - 9(6) = 216 - 54 = 162
f(a) = f(1) = 1³ - 9(1) = 1 - 9 = - 8
average rate of change =
=
= 34
Answer:
<u>Q/ Draw a line ; Ans; </u>

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .
Ans; 7/3—> 2 1/3
*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .
Ans; 12/10 —> 1 1/5
*explain; simple (12 and 10) ÷ 2 so equal 6/5
We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

<u>Q/ Compare the fractions;Ans;</u>

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6
13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .
<u>Q/Add; Ans;</u>


<u>Q/Subtract; Ans;</u>


<u>Q/ Multiply;Ans;</u>


<u>Q/Divide;Ans;</u>


I hope I helped you^_^