PLEASE HELP ME FAST!!!

Solve for n. <br><br><br> 4(n-7)-(2-5n)=8n

Kisachek [45]

Answer:

n = 30

Step-by-step explanation:

4(n - 7) - (2- 5n) = 8n ← distribute parenthesis on left side

4n - 28 - 2 + 5n = 8n

9n - 30 = 8n ( subtract 8n from both sides )

n - 30 = 0 ( add 30 to both sides )

n = 30

4 0

3 years ago

Read 2 more answers

PLEASE HELP FAST!! and also please show your work!!

Maru [420]

Answer:

a

Step-by-step explanation:

w+3=-4*3

or,w+3=-12

or,w=-12-3

w=-15

3 0

3 years ago

Anyone can help wright answers only

dimaraw [331]

Answer:

subtitute the value of x and y to the expression.

Step-by-step explanation:

21.

$4 {x}^{2} + 30y = 4 \times {7}^{2} + 30 \times 2$

$= 196 + 60 = 256$

7 0

3 years ago

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0

3 years ago

For the soccer banquet, the players and their family members selected their favorite main dish and side dish. Of the 39 people w

Oduvanchick [21]

Question:

For the soccer banquet, the players and their family members selected their favorite main dish and side dish. Of the 39 people who chose chicken as the main dish, 18 wanted potatoes. Of the 32 people who chose rice as a side dish, 6 chose fish as a main dish. A total of 8 people chose a vegetarian meal with potatoes, and a total of 10 people chose fish as their main dish.

Which two-way table correctly displays this data?

a. A 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 18, 21, 39. The third column is labeled Fish with entries 4, 6, 10. The fourth column is labeled Vegetarian with entries 8, 5, 13. The fifth column is labeled total with entries 30, 32, 62.

b. A 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 21, 18, 39. The third column is labeled Fish with entries 6, 4, 10. The fourth column is labeled Vegetarian with entries 5, 8, 13. The fifth column is labeled total with entries 32, 30, 62.

c. A 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 14, 18, 32. The third column is labeled Fish with entries 6, 4, 10. The fourth column is labeled Vegetarian with entries 19, 8, 27. The fifth column is labeled total with entries 39, 30, 69.

d. A 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 18, 14, 32. The third column is labeled Fish with entries 4, 6, 10. The fourth column is labeled Vegetarian with entries 8, 19, 27. The fifth column is labeled total with entries 30, 39, 69.

Answer:

b. A 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 21, 18, 39. The third column is labeled Fish with entries 6, 4, 10. The fourth column is labeled Vegetarian with entries 5, 8, 13. The fifth column is labeled total with entries 32, 30, 62.

Step-by-step explanation:

The question above is a two way table because it consists of two tables that are arranged in a column and row format or design.

A two way table is a table that up of values or numbers or frequencies for two variables. One of the variables is placed in a column while the other is placed in a row.

In the question above, we where given two variables, variable one is the main dish while variable two is the side dish. The proper way to display the data correctly is to

Create a 5-column table has 3 rows. The first column has entries Rice, Potatoes, Total. The second column is labeled Chicken with entries 21, 18, 39. The third column is labeled Fish with entries 6, 4, 10. The fourth column is labeled Vegetarian with entries 5, 8, 13. The fifth column is labeled total with entries 32, 30, 62.

Therefore, Option b. is the correct option.

5 0

4 years ago

Read 2 more answers