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givi [52]
3 years ago
5

(-1) + 1 = 0 is which inverse​

Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

Heya mate....

Step-by-step explanation:

This is ur answer....

<h2><em>-</em><em>-</em><em>></em><em> </em><em>ADDITIVE INVERSE!</em></h2>

<em>Additive inverse simply means chan</em><em>ging the sign of the number and adding it to the original number to get an answer equal to 0. The properties of additive inverse are given below, based on negation of the original number. For example, x is the original number, then its additive inverse is -x.</em>

Hope it helps you,

mark me brainliest pls.....

Follow me! :)

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Find the sum or difference 5/6 + 4/9
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The closest option to the actual answer is a.

1 5/18 is the actual answer.

If you make both the denominators the same, then you can actually add the fractions together.

To make both of the denominators the same, you need to multiply 5/6 by 9 and 4/9 by 6, which would result in 45/54 + 24/54= 69/54 = 23/18. If we convert it to a mixed fraction, it would result into 1 5/18.
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3 years ago
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omeli [17]
I believe the mode is 5 because there are four 5’s which is the most of a certain number in this list.
8 0
2 years ago
Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
Need help don’t know what I’m doing
docker41 [41]
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language) 
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Step-by-step explanation:

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6 0
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