V=a*b*c, a=(2+1/2), b=(2+1/2), c=(6+1/2)
V=(2+1/2)*(2+1/2)*(6+1/2) = 15/2 = 7+1/2
(seven whole and one second)
Answer:
The probability of founding exactly one defective item in the sample is P=0.275.
The mean and variance of defective components in the sample are:

Step-by-step explanation:
In the case we have a lot with 3 defectives components, the proportion of defectives is:

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).
The probability of having one defective in the sample is:

b) The mean and variance of defective components in the sample is:

The Chebyschev's inequality established:

Answer:
X= 30-4r/-6
Step-by-step explanation:
1. Move the 9 to the other side. (21+9=30)
2. subtract the 4r and move it to the other side (-6x=21-4r)
3. divide both sides by -6
Answer:
all i see is ..........
Step-by-step explanation:
Use the distributive property:
5*b+5*2+b=20
5b+10+b=20.
Combine like terms:
6b+10=20.
Subtract 10 from both sides:
6b+10-10=20-10
6b=10.
Divide both sides by 6:
6b/6=10/6
b=5/3=1 2/3.
Brian travels 1 2/3 hours. This means Annie travels
5(1 2/3+2)=5(3 2/3)=5(11/3)=55/3=18 1/3 hours.
Hope this helps!