All categories

3 years ago

Why was the Cumberland Gap a good place for a trail?

Geography

1 answer:

fiasKO [112]3 years ago

7 0

Answer:

The Cumberland Gap is one of the few crossable places in the entire lower Appalachians, making it a safe and convenient place to cross the Appalachians in many seasons.

Explanation:

You might be interested in

Imagine that you have obtained spectra for several galaxies and have measured the observed wavelength of a hydrogen emission lin

Lerok [7]

Answer:

A. z (galaxy 1) = -0.00515, z (galaxy 2) = -0.01707, z (galaxy 3) = -0.04008

B. v (galaxy 1) = -0.00517c, v (galaxy 2) = -0.01707c, v (galaxy 3) = -0.0401c

C. d (galaxy 1) = -21 Mpc,d (galaxy 2) = -69.4 Mpc, d (galaxy 3) = -163 Mpc

Explanation:

We begin by listing out the parameters we were given:

λ (obsv) = 656.3 nm, λ (emit 1) = 659.7 nm, λ (emit 2) = 667.7 nm,

λ (emit 3) = 683.7 nm

A) Using the Redshift formula, we have:

z = [λ (obsv) - λ (emit)] ÷ λ (emit)

For galaxy 1:

z = [λ (obsv) - λ (emit 1)] ÷ λ (emit 1)

z = (656.3 - 659.7) ÷ 659.7 = -0.00515

z = -0.00515

For galaxy 2:

z = [λ (obsv) - λ (emit 2)] ÷ λ (emit 2)

z = (656.3 - 667.7) ÷ 667.7 = -0.01707

z = -0.01707

For galaxy 3:

z = [λ (obsv) - λ (emit 3)] ÷ λ (emit 3)

z = (656.3 - 683.7) ÷ 683.7 = -0.04008

z = -0.04008

B) Using the Doppler formula, we have:

(Δλ ÷ λ) = v ÷ c

v = c * (Δλ ÷ λ)

but, z = (Δλ ÷ λ)

⇒ v = c * z

speed of light (c) = 3 x $10^{8}$ m/s

For galaxy 1:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.00515)

v = -1.55 x $10^{6}$ m/s

v = -0.00517c

For galaxy 2:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.01707)

v = -5.12 x $10^{6}$ m/s

v = -0.01707c

For galaxy 3:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.04008)

v = -12.03 x $10^{6}$ m/s

v = -0.0401c

N.B: the negative value of velocity connotes that the galaxies are moving away from us (not towards us)

C) Using Hubbleʹs law, we have:

v = H · d

where:

v = velocity of a galaxy (km/s), d = distance (Mpc),

H = Hubble's constant (km/s/Mpc) = 73.8 km/sec

d = v ÷ H

We use the velocities calculated in B) above

For galaxy 1:

v = -1.55 x $10^{3}$ km/s

d = -1.55 x $10^{3}$ ÷ 73.8

d = -21 Mpc

For galaxy 2:

v = -5.12 x $10^{3}$ km/s

d = -5.12 x $10^{3}$ ÷ 73.8

d = -69.4 Mpc

For galaxy 3:

v = -12.03 x $10^{3}$ km/s

d = -12.03 x $10^{3}$ ÷ 73.8

d = -163 Mpc

N.B: distance cannot be a negative value

4 0

3 years ago

How geography is related to mathematics

STALIN [3.7K]

Answer:

In a lot of ways for example finding how large or small a part of a map is.

Explanation:

7 0

3 years ago

___________ means “on or near the sea.”

Svet_ta [14]

Maritime is the answer

6 0

3 years ago

Read 2 more answers

True or false Different abiotic factors affect each marine ecosystem

REY [17]

I believe its true, i'm not entirely sure.

4 0

3 years ago

Read 2 more answers

Decide whether each statement is true or false or choose the best answer to make each statement true.

erastova [34]

Answer:

As given below.

Explanation:

1. False, as the number of daylight hours on the globe are mapped by the location f places over the various latitudes and altitudes. And the sun is not with the same both rise and set at both the hemispheres.

2. Yes, there exist changes of 12 hours in sunlight and darkness on earth due to the rotational speed of the earth on its axis as the earth is tilted 23.5 degrees so in both the hemisphere there exists equinoxes and solstices.

3. True, as the known fact the earth rotates in anticlockwise direction hence the eastern side gets to see the sun first and western side later this rule applies everywhere in the earth on both the equinoxes.

4. True, The celestial poles and equator are two points on earth that represent the equinoxes and the point that falls directly over the poles is called the zenith and the plane that touches is called the galactic plane.

8 0

3 years ago