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Ronch [10]
2 years ago
7

Solve. Show your work 1 1/4 × 3 1/2​

Mathematics
2 answers:
AnnZ [28]2 years ago
6 0

Answer:

\frac{38}{8}  \: or \: 4 \frac{3}{8}

Step-by-step explanation:

1 \frac{1}{4}  \times 3 \frac{1}{2}

\frac{5}{4}  \times  \frac{7}{2}

\frac{38}{8}

Into mixed fraction

4 \frac{3}{8}

<h3>Hope it is helpful....</h3>

algol132 years ago
4 0

Answer:

\frac{38}{5}

Step-by-step explanation:

1 \frac{1}{4}  \times 3 \frac{1}{2}

\frac{5}{4}  \times  \frac{7}{2}

\frac{38}{8}

Into mixed fraction:

4 \frac{3}{8}

Into decimal form :

4.375

<h2>Hope it is helpful....</h2>
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8 0
3 years ago
G=x-c/x. for x<br><br>how do yoy make this an equation for x? help
zzz [600]
1.
\displaystyle \text{if }\quad G=x-  \frac{C}{x} \\\\

x \neq 0

Multiply both sides by x:

\displaystyle Gx=x\bigg(x- \frac{C}{x}\bigg )\\\\Gx=x^2-C

Subtract from both sides Gx:
Gx-Gx=x^2-C-Gx\\x^2-Gx-C=0

Then solve this equation:

\displaystyle x^2-Gx-C=0\\\\x_{1,2}= \frac{G\pm  \sqrt{G^2+4C} }{2}

2.
\displaystyle\text{if}\quad G= \frac{x-C}{x}

x \neq 0

Multiply both sides by x:

Gx=x-C

Subtract from both sides Gx:

x-C-Gx=0

Then solve this equation:

\displaystyle x-Gx-C=0\\x(1-G)=C\\x= \frac{C}{1-G}




7 0
3 years ago
Qbjsksnnfkkdnnwnnsiodnnjfkjbbskkxkkdn
iris [78.8K]

Answer:

There are 25 students in the class.

Step-by-step explanation:

Since we know the percentage of students who want an ice cream party is 20%, and 5 students want an ice cream party, we know that:

\frac{5}{S}=0.2

, where S is the total amount of students. We can then solve for S:

\frac{5}{S}=0.2 Given equation

5=0.2*S Multiply by S

25=S Divide by 0.2

Therefore, there are 25 students in the class.

7 0
3 years ago
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Worth 12 points and actually help me with the question plz
KATRIN_1 [288]

Answer:

(x + 1, y - 3)

Step-by-step explanation:

The translation is 1 unit right and 3 units down.

7 0
3 years ago
Given that g(x) = 2x ^ 2 - 2x + 8 , find each of the following. a) g(0) b) g(- 2) C) g(3) d) g(- x) e) g(1 - t)
raketka [301]

Answer:

g(-2)=20

Step-by-step explanation:

Given g(x)=2x^2-2x+8, substitute what is in the parentheses for x to find an output.

For g(-2), the term -2 is in the parentheses. Thus, substitute x=-2 into 2x^2-2x+8 to find g(-2):

g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}

5 0
2 years ago
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