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3 years ago

1. Adjacent angles are two angles in the same plane with a common

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

Adjacent angles are two angles in the same plane with a common VERTEX and a common SIDE but no common interior points.

Step-by-step explanation:

Adjacent angles share a common side on the same vertes, but they do not overlap each other.

In the attached image, ∠ABD is adjacent to ∠DBC, but ∠ABC is not adjacent to any of them.

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4 1/12 + 1 3/4 = ? Fractions please help I'm tired.

AfilCa [17]

Lets just convert them into improper fractions.

1) 4 and 1/12 = 49/12.

1 and 3/4 = 7/4.

2) 7/4 = 21/12

3) 21/12 + 49/12 = 70/12

Back to mixed fractions!

70/12 = 5 and 10/12 = 5 and 5/6

=5 5/6

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

There is another method if you want to know. You can simply just do 4 + 1 = 5. Then do 1/12 + 3/4 = 10/12 = 5/6. So it goes to 5 5/6. Your choice which ever you find more eas.

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2 years ago

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Can someone help me please

Oxana [17]

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3 3/4 = 3.75
21/6 = 3.5

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3 years ago

Please help! I need to answer this last question, and it was due last night!! Will chose Brainliest!! Just find the missing meas

svp [43]

If it’s an angle I think 90% but if not maybe 24 all around

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3 years ago

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3 years ago

Which is the simplified form of (2ab/a^-5b^2)^-3?

olchik [2.2K]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

$(\frac{2ab}{a^{-5}b^2})^{-3}$

We will use law of exponents :

$(\frac{2ab}{a^{-5}b^2})^{-3}\\\\=(\frac{a^{-5}b^2}{2ab})^3\text{ }\because (a^m)^{-1}=\frac{1}{a^m}\\\\=\frac{a^{-15}b^{6}}{8a^3b^3}\text{ }\because (a^m)^n=a^{mn}\\\\=\frac{b^{6-3}}{a^{3+15}}\\\\=\frac{b^3}{8a^{18}}$

So, the simplified form is

$\frac{b^3}{8a^{18}}$

Hence, First option is correct.

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3 years ago

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