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zaharov [31]
2 years ago
10

A 28 foot ladder is propped against a wall. The base of the ladder is 19 ft from the wall how far up the wall does the ladder go

Mathematics
1 answer:
docker41 [41]2 years ago
8 0

Answer:

20.6

Step-by-step explanation:

The problem can be solved by applyPythagoreanean theory

a^2+b^2= c^2

19^2 + b^2= 28^2

361 + b^2= 784

b^2= 784-361

= 423

b= √423

= 20.6

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2 years ago
I need help on this plzzz
NISA [10]

Answer:

see below

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles.

139 = <Q + <P

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139 = 10y+9

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Divide each side by 10

13 = y

<P = 4y+8 = 4*13+8 = 60

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3 0
3 years ago
Belinda wants to bye 5 pictures to hang in her family room.if each picture cost $30.90 how much will it cost her to buy all 5?
andre [41]
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5 0
3 years ago
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Alchen [17]
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5 0
3 years ago
A rotating light is located 20 feet from a wall. The light completes one rotation every 3 seconds. Find the rate at which the li
ss7ja [257]

Answer:

43.17 ft/s

Step-by-step explanation:

Let the height of the wall is y.

distance of wall from light is 20 feet.

tan\theta =\frac{y}{20}    

y = 20 tanθ    .... (1)

time period, T = 3 second

\frac{d\theta}{dt}=\frac{2\pi}{3}

Differentiate equation (1) with respect to t.

\frac{dy}{dt}=20sec^{2}\theta\times \frac{d\theta}{dt}

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dy/dt = 20 x 2.16

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4 0
3 years ago
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