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zaharov [31]
3 years ago
10

A 28 foot ladder is propped against a wall. The base of the ladder is 19 ft from the wall how far up the wall does the ladder go

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Answer:

20.6

Step-by-step explanation:

The problem can be solved by applyPythagoreanean theory

a^2+b^2= c^2

19^2 + b^2= 28^2

361 + b^2= 784

b^2= 784-361

= 423

b= √423

= 20.6

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Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,ax
Ivan

Given:

The function is:

f(x)=-2x^2+7x+4

To find:

Express the quadratic equation in the form of f(x)=a(x-h)^2+k, then state the minimum or maximum value,axis of symmetry and minimum or maximum point.

Solution:

The vertex form of a quadratic function is:

f(x)=a(x-h)^2+k              ...(i)

Where, a is a constant, (h,k) is the vertex and x=h is the axis of symmetry.

We have,

f(x)=-2x^2+7x+4

It can be written as:

f(x)=-2\left(x^2-3.5x\right)+4

Adding and subtracting square of half of coefficient of x inside the parenthesis, we get

f(x)=-2\left(x^2-3.5x+(\dfrac{3.5}{2})^2-(\dfrac{3.5}{2})^2\right)+4

f(x)=-2\left(x^2-3.5x+(1.75)^2\right)-2\left(-(1.75)^2\right)+4

f(x)=-2\left(x-1.75\right)^2+2(3.0625)+4

f(x)=-2\left(x-1.75\right)^2+6.125+4

f(x)=-2\left(x-1.75\right)^2+10.125                ...(ii)

On comparing (i) and (ii), we get

a=-2,h=1.75,k=10.125

Here, a is negative, the given function represents a downward parabola and its vertex is the point of maxima.

Maximum value = 10.125

Axis of symmetry : x=1.75

Maximum point = (1.75,10.125)

Therefore, the vertex form of the given function is f(x)=-2\left(x-1.75\right)^2+10.125, the maximum value is 10.125, the axis of symmetry is x=1.75 and the maximum point is (1.75,10.125).

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3 years ago
Find the measure indicated
lesantik [10]

Answer:

B) 69°

Step-by-step explanation:

The missing measure is supplementary angle of 111° which means their sum is equal to 180°

180 - 111 = 69.

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