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zaharov [31]
2 years ago
10

A 28 foot ladder is propped against a wall. The base of the ladder is 19 ft from the wall how far up the wall does the ladder go

Mathematics
1 answer:
docker41 [41]2 years ago
8 0

Answer:

20.6

Step-by-step explanation:

The problem can be solved by applyPythagoreanean theory

a^2+b^2= c^2

19^2 + b^2= 28^2

361 + b^2= 784

b^2= 784-361

= 423

b= √423

= 20.6

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What is the equation of the function shown in the graph provided?<br><br> y= _ x + _
Mkey [24]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

x-intercept (-2, 0)

y-intercept (0, -6)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                  m=\frac{-6-0}{0+2}
  2. Subtract/Add:             m=\frac{-6}{2}
  3. Divide:                        m=-3

<u>Step 3: Redefine</u>

Slope <em>m</em> = -3

y-intercept <em>b</em> = -6

<u>Step 4: Write linear equation</u>

Slope-Intercept Form:   y = -3x - 6

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