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maria [59]
3 years ago
14

What is 2324132352413142536-1342536435241342536/2354253643524125363541+425364763524142536475

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0

That is going to be a looong answer...

2324132352413142536 -  \frac{1342536435241342536}{2.354254e}  - 21 + 425364763524142536475

and done

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Please help me for 100 points and don't put in no fake answers -_-
Bad White [126]

Answer:

n=14

n=30

hope this helped

3 0
3 years ago
Read 2 more answers
4x^2+12x-8 <br>Can you find the get?​
nata0808 [166]

Answer:

4(x^2+3x-2)

Step-by-step explanation:

This is the equation factored!

8 0
3 years ago
Adrian spent $19.35 on school supplies he bought two poster boards for $2.25 each he spent the remaining amount on notebooks tha
dusya [7]
9 because when you subtract the amount of poster money from the total ($19.35), you get $14.85. $14.85 divided by $1.65 is 9, which means he bought 9 notebooks.
4 0
3 years ago
A group of friends compared the number of text messages they sent in one week.
Ivan

Answer:

<u>The sample that best represents the population is the sample of the last eight friends </u>

Step-by-step explanation:

Let's find out the sample that best represents the population, this way:

Mean of the number of text messages a group of 24 friends sent in one week = 10,700/24 = 445.83

Mean of the sample of the first six friends = 1,850/6 = 308.33

Mean of the sample of the first ten friends = 3,300/10 = 330

Mean of the sample of the last twelve friends = 6,500/12 = 541.67

Mean of the sample of the last eight friends = 4,150/8 = 518.75

<u>The sample that best represents the population is the sample of the last eight friends, because its mean is the closest to the population mean (445.83 and 518.75)</u>

5 0
4 years ago
(a) suppose that the displacement of an object is related to time according to the expression x = bt2. what are the dimensions o
Margaret [11]
Displacement x would be in terms of length, while t would be in terms of time.
Therefore the equation would have units of:
length = (b)*time^2
b = length/(time^2)
Therefore, the units of the constant b should be in length per time^2 (for example, in m/s^2, such as in acceleration).
7 0
3 years ago
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