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ivolga24 [154]
2 years ago
7

Find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree.

Mathematics
1 answer:
podryga [215]2 years ago
8 0

Answer:

\cos( \theta)  =  \frac{ - \sqrt{}  7}{5}  \\  \theta =  \cos {}^{ - 1} (  \frac{ \sqrt{}  - 7}{5} ) \\  \theta = 58.1 \degree, \: 121.9 \degree,  \: 238.1 \degree

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Answer:

So, The possible values of h and r are

1. r = 3 , h = 3

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Step-by-step explanation:

P.S - The exact ques is -

As we know that Volume of cone , V = \frac{1}{3}\pi r^{2}h

As given,

V = 9\pi

⇒\frac{1}{3}\pi r^{2}h = 9\pi \\  \frac{1}{3} r^{2}h = 9 \\r^{2}h = 27

So,

The possible values of h and r are

1. r = 3 , h = 3

2. r = 1, h = 27

3. r = 2, h = 6.75

In Case I-

When r = 3, h = 3

(3)² ×3 = 9×3 = 27

Satisfied

Case II-

r = 1, h = 27

(1)²×27 = 1×27 = 27

Satisfied

Case III-

r = 2, h = 6.75

(2)²×6.75 = 4×6.75 = 27

Satisfied

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