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ankoles [38]
3 years ago
6

Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
valkas [14]3 years ago
7 0

hi

Step-by-step explanation:

bffhrhehhegeeh33g3g3

Tanzania [10]3 years ago
3 0
Ok ok answer is 89898
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29 homework problems

15 + 5 + 9 = 29
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Select the term that describes the constant portion in this quadratic equation.
trasher [3.6K]
The constant potion contains no variables ( no 'x')

So its 16
6 0
3 years ago
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1. Melissa went to lunch with two friends. She purchased 3 corn dogs, 2 fruit cups, and
umka2103 [35]

Answer:

14 is the answer.

Step-by-step explanation:

8 0
3 years ago
What is the rule of the function table?
Leokris [45]

Answer:

y = 3x - 2

Step-by-step explanation:

The 'rule' of a function table is the expression which you use to put in a value of 'x' to get the value of 'y'.  In this case you can look at the table and look for a pattern of 'x' and 'y' values:

       +1  +1  +1  

x = 1    2    3    4  

y = 1    4    7    10

      +3   +3   +3

So, the 'x' is increasing by 1 each time and the y is increasing by 3.  However, what is 'y' when 'x' is 0?  Subtract 1 - 0 to get x = 0 and subtract 1 - 3 to get the value of 'y' or y = 1-3 = -2.  

If we multiply x by 3 and subtract -2:  3x - 2, then we should get our value of 'y' each time:

y = 1(3) - 2 = 1

y = 2(3) -2 = 4

y = 3(3) - 2 = 7

y = 4(3) - 2 = 10

3 0
3 years ago
If (a+10) and (a+20)are supplementary angles,find them​
motikmotik

Given:

(a+10) and (a+20) are supplementary

To find:

Each angle

Steps:

if 2 angles are supplementary that means they add up to 180°

(a + 10) + (a + 20) = 180

   a + 10 + a + 20 = 180

              2a + 30 = 180

                      2a = 180 - 30

                      2a = 150

                        a = 150/2

                        a = 75°

Now let's find value of each angle,

a + 10 = 75 + 10

          = 85°

a + 20 = 75 + 20

           = 95°

Therefore, the value of each angle is 85° and 95° respectively

Happy to help :)

If you need any help feel free to ask

4 0
3 years ago
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