I and III seem to be correct, II doesn't because, for example, if x = w = z = t = 70 and y = u = 40, then all three pairs of vertical angles in the figure have equal measure and the given condition x + y = u + w stands. But it means y is not equal to w.
Answer:

Step-by-step explanation:
![\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7Bx%5E2%28y-2%29%7D%7B3y%7D%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%203%2C%20%5C%20y%20%3D%20-1%5C%5C%5C%5C%3D%20%5Cfrac%7B%283%29%5E2%28-1-2%29%7D%7B3%28-1%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B9%28-3%29%7D%7B-3%7D%20%5C%5C%5C%5C%3D%209%20%5C%5C%5C%5C%20%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Hello There!
It is represented as: h =
Hope This Helps You!Good Luck :)
- Hannah ❤
If there is such a scalar function <em>f</em>, then



Integrate both sides of the first equation with respect to <em>x</em> :

Differentiate both sides with respect to <em>y</em> :


Integrate both sides with respect to <em>y</em> :

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :



Integrate both sides with respect to <em>z</em> :

So we end up with
