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Schach [20]
2 years ago
12

For DE=29,find the length of segment BC

Mathematics
1 answer:
LenKa [72]2 years ago
7 0
Triangle ABC is similar to triangle ADE.

The scale factor from ADE to ABC is 2. We know this because two of the sides on the triangle are equally divided into 2.

29(2) = 58

BC = 58
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a shopkeeper purchased a TV at ₹15,000 and gives a discount of 20% on its marked prize and still got a profit of 8% . find the m
Setler79 [48]

\huge\sf\underline{Answer}

\sf\longrightarrow selling \: prize \:   =  \frac{100 + profit\%}{100}  \times cp

\sf\longrightarrow  \frac{108}{100}  \times 15000 = 16200

Let the marked prize of the TV be x .

\sf\longrightarrow discount = 20\% \: of \: x \:  =  \frac{20}{100}x =  \frac{x}{5}

We have SP = MP - Discount

\sf\longrightarrow 16200 \:  =  \: x -  \frac{x}{5}

\sf\longrightarrow 16200 \:  =  \frac{4x}{5}

\sf\longrightarrow x \:  =  \: 20250

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7 0
2 years ago
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Schach [20]

Answer:

5/2

Step-by-step explanation:

6 0
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X^2 - y^2 = 100
luda_lava [24]

Answer:

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Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

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2 years ago
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Answer:

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Step-by-step explanation:

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