Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
y = 2
Step-by-step explanation:
The mid segment HJ is half of the third side GK , that is
HJ = 
GK , substitute values
2y = (y + 6) ← multiply both sides by 2 to clear the fraction
4y = y + 6 ( subtract y from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer:
5
Step-by-step explanation:
3(14+x) = 57
42 +3x = 57
3x = 15
x = 5
Answer:
Scalene
Step-by-step explanation:
Because all of the sides are different lengths
