Hey there!
Let's create a systems of equations using x and y.
4x+3y=15
3x-2y=7
We need to solve this using elimination. First, we need to multiply the first equation by 2/3 so that we can cancel out the y's when combining our equations.
2 2/3x+2y=10
3x-2y=7
Now we combine the equations...
5 2/3x=17
x=3
Now we can plug our x into the first equation to find y.
12+3y=15
y=1
Our numbers are 3 and 1.
I hope this helps!
Answer:
-6x+5y+8
Step-by-step explanation: subtract 9xfrom 3x
Subtract 2 from 10
-6x+5y+10-2
-6x+5y+8
Step-by-step explanation:
1 .f(x)=
-x+1
f(-1)= (-1)-(-1)+1
f(-1)= 1+1+1
= 3
3.f(x)=-x+1
f( 1)=(1)-1+1
f( 1)=1-1+1
=1
5. f(x)=-x+1
f(3)=
-3+1
= 9-3+1
=7
2. g(x) = 5 - 3x
g( -8)=5-3(-8)
g( -8)=5+24
=29
4.g(x) = 5 - 3x
g(5)=5-3(5)
g(5)=5-15
=-10
6.g(x) = 5 - 3x
g(-3)=5-3(-3)
g(-3)=5+9
=14
7 because 42 divided by 6= 7 and length times width = perimeter
<span><span> x-4/x3-64</span> </span>Final result :<span> x4 - 64x3 - 4
—————————————
x3 </span>
