Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
line
Step-by-step explanation:
that is a line in the form y = mx + b
slope = m = 3
y intercept = b = 7
Well x=1 always unless it tells you other wise so 1+0.5 would equal 1.5 and so after that you keep adding so 1.5 + 0.5 equal 2 so you keep taking the previous answer and adding 0.5 to it
Well if it pumps 4 2/5 per minute that is equal to 4 4/10 in a minute or 4.4 because you multiply the top and bottom of the fraction by two. it’s still the same fraction but it is easy to convert to a decimal now. you could use this fraction but it’s much easier to use decimals. Because the first number is a decimal you should make the second one a decimal too. To do this you need to know that 1/4 of 100 is 25. so now we have these numbers and all you do now is divide 17.25 by 4.4 which could be rounded to 4 because it’s a long decimal
Let's simplify step-by-step.
23
p
+
43
p
−
13
p
=
23
p
+
43
p
+
−
13
p
Combine Like Terms:
=
23
p
+
43
p
+
−
13
p
=
(
23
p
+
43
p
+
−
13
p
)
=
53
p
Answer:
