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barxatty [35]
3 years ago
5

Determine the intercepts of the line

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0

Answer:

x-intercept: -1/7

y-intercept: 1/4

Step-by-step explanation:

change equation into standard form:  7x - 4y = -1

set 'x' to zero and solve for y:  0 - 4y = -1

                                                        y = 1/4

set 'y' to zero and solve for x:  7x - 0 = -1

                                                        x = -1/7

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Step-by-step explanation:

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8*10^4 is how many times as big as 4*10^-5
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80000/0.0004 = 2'000'000'000 or 2 x 10^-9

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The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?
mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

=\frac{-6\pm\sqrt{37\times 4}}{8}

=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}

=\frac{-6\pm\sqrt{37}\times 2}{8}

=2\frac{(-3\pm\sqrt{37})}{8}

=\frac{-3\pm\sqrt{37}}{4}

x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

=\frac{-3}{2}

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

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3 years ago
What is 20 % of 82.98
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4 years ago
Which expression is equivalent to logc x^2-1/5x?
fenix001 [56]

Answer:

log(x²-1)-(log5+logx)

Step-by-step explanation:

For this problem we need to make use of two existing logarithmic properties. These are:

  • logM/N is equal to logM - logN
  • logMN is equal to logM+logN

Following the first property, we can simplify the expression to:

log(x²-1)-log5x

Then, we will use the second property to the term 5x. The final form of the expression would then be:

log(x²-1)-(log5+logx)

Thus the answer is log(x²-1)-(log5+logx)....

4 0
3 years ago
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