Answer:
a=1
b= 1/16
c= 1/256
d= 1
e= 4/9
f= 16/81
Step-by-step explanation:
Plug in the values of X on the left side of the table into the function on the right side of the table. Remember that negative exponents mean the number is under a fraction. 4^-0 is like saying one over 4^0.
For the blue table, because the numbers are already in a fraction and in parentheses, you apply the exponent to each number individually.
Answer: Both A, and C
Step-by-step explanation:
The answer to the first system of equations (2x+2y=16) would be
x=3 and y=5 ( 3x-y=4 )
Which means we have to find out which of the other equations has an x value of 3, and a y value of 5.
If A is 2x+2y=16, then x=3 and y=5
6x-2y=8
If B is x+y=16, then x=5 and y=11
3x-y=4
If C is 2x+2y=16, then x=3 and y=5
6x-2y=8
If D is 6x+6y=48 , then x=-2 and y=10
6x+2y=8
Both A and C are equal to the first system of equations, which means they are both correct answers.
Answer:
sin(theta) + cos(theta) = 0
sin(theta) = -cos(theta)
sin(theta)/cos(theta) = -1
tan(theta) = -1
theta = - 45° ± k·180°
Answer:
Step-by-step explanation:
Look what happens if you do the multiplication of P(x):
P(x) = x^3 - 9x
This is a variation of the basic cubing function y = x^3.
The graph begins in QIII and ends in QI; in other words, if you go left the graph drops; if you go right, the graph rises (without limit, in both cases).
Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
, 
,
, 
,
, 
,
, 
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
