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lesya [120]
2 years ago
8

1. Anne wants to join five pieces of paper together. She plans to use 3 rectangular pieces of the same size and 2 square pieces

of the same size. The length of each rectangular piece is 3 1/2 feet. The width of each rectangular piece, w, is the same as the length of each square piece. The expression below can be used to find the total surface area of the five pieces of paper. Anne decides that the width, w, of the rectangular pieces should be 2 feet. What is the total surface area, in square feet, of all five pieces of paper?
Mathematics
1 answer:
Artyom0805 [142]2 years ago
8 0

Answer and explanation:

Surface area of a rectangle = length * width

Surface area of a square = a² where a is length of a side

To find total surface area of the the five pieces of paper, we add up all the areas of all the shapes

Given that length of rectangle =3.5

And width = 2

Area of rectangle =3.5*2=7

Area of 3 rectangles given they are all equal = 7*3=21

Since width of rectangle equal to width of square and all sides of square are equal

Area of square = 2 *2 =4

Area of the two squares =4*2=8

Total surface area of the five plane shapes = 21+8= 29

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Answer:

Troy ate 7 lollies.

Step-by-step explanation:

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Because Tane ate <u>8</u><u> out of the 24</u> lollies and Levi ate <u>9</u><u> out of the 24 lollies</u>, that indicates that <u>17</u><u> out of the 24 lollies</u> are gone (just add your results, 8+9=17). This leaves Troy with only 7 lollies (<em><u>subtract 17 from 24</u></em> to find out how many lollies are left, 24-17=7).

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2 years ago
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3 years ago
a right triangle has a non hypotenuse side length of 45" and the hypotenuse measures 53". What is the length of the other non-hy
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Help pleaseee will mark brainliest
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Ais the answer I’m pretty sure
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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

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