Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is
Answer:
f(x) = ( 1/3) ^ (x)
Step-by-step explanation:
The function is
f(x) = (1/3) ^ (x)
When x = 1 f(x) = 1/3
when x=2 f(x) = 1/9
When x = -1 f(x) = ( 1/3) ^ -1 = 3/1 =3
Answer:
angle KJG = angle FGJ (by alternateinteriorangle)
Y-intercept (0, 1)
Equation of asymptote y=0
Equation of asymptote can also be called horizontal asymptote.
It means the place where the line almost meets but actually not touching the place. The line almost touches y=0 but it actually does not touch it.
The bank account owner is withdrawing money at the rate of $50/month. The account balance is steadily declining.
