Let
Vco------------------- >Volume cone
Vcy------------------ >Volume cylinder
r= 8mm
hco----------- > height of cone=18 mm
hcy------------ > height of cylinder =54-18=36 mm
then
Vco=π*r² *hco/3--------- > π*8² *18/3=π*384 mm³
Vcy=π*r² *hcy--------- > π*8² *36=π*2304 mm³
the total cubic millimeters of sand=Vco+Vcy=π*384+π*2304=π*2688
if 10π cubic millimeters --------------------- > 1 seg
π*2688--------------------------------- X
X=π*2688/10π=268.8 seg
the answer is 268.8 seg
we know that
if ∠UVW and ∠XYZ are complementary angles
then
∠UVW + ∠XYZ=90°
∠UVW=x-10
∠XYZ=4x-10
substitute the values
(x-10)°+(4x-10)°=90°
Solve for x
5x-20=90
5x=90+20
5x=110
x=22°
∠UVW=x-10=22-10=12°
∠XYZ=4x-10=4*22-10=78°
therefore
<u>the answer is</u>
x=22°
∠UVW=12°
∠XYZ=78°
Answer:
y is the dependent variable
Step-by-step explanation:
