1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Musya8 [376]
3 years ago
6

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

please help thanks
A.
9 units, 12 units
B.
11 units, 10.2 units
C.
4.9 units, 15.8 units
D.
4.9 units, 14.2 units
E.
5.2 units, 14.1 units
Mathematics
1 answer:
MrMuchimi3 years ago
6 0
I think it is C but i could be wrong tho
You might be interested in
Find all sides of a right triangle whose perimeter is equal to 60 cm and its area is equal to 150 square cm
miskamm [114]

Answer:

15cm by 20cm by 25cm

Step-by-step explanation:

Let the sides of the right angle be x, y and h

x is the breadth

y is the height

h is the hypotenuse

Perimeter = x + y + h

x + y +h  = 60

x+y = 60-h .... 1

If its area is equal to 150 square cm, then;

Area = 1/2 * base * height

Area = 1/2 *x * y

xy/2 = 150

xy = 300 ....2

According to pythagoras theorem;

x² + y² = h²

On expanding x² + y²

x² + y² = (x+y)² - 2xy

The equation becomes

(x+y)² - 2xy = h² ... 3

Substitute equation 1 and 2 into 3;

From 3;

(x+y)² - 2xy = h² ... 3

(60-h)² - 2(300) = h²

3600-120h + h² - 600 = h²

3600-120h - 600 = 0

-120h = 600-3600

-120h = -3000

h = 3000/120

h = 25cm

Recall that x+y+h = 60

x+y+25 = 60

x+y = 60 - 25

x+y = 35 ... 4

From equation 2;

xy = 300

x = 300/y ..... 5

Substitute 5 into 4;

300/y + y = 35

(300+y²)/y = 35

300+y² = 35y

y²-35y + 300 = 0

y²-20y-15y + 300 = 0

y(y-20)-15(y-20) = 0

y-20 = 0 and y - 15 =0

y = 20 and 15

since x+y = 35

x + 20 = 35

x = 35 - 20

x = 15

Hence the sides of the triangle are 15cm by 20cm by 25cm

8 0
3 years ago
The two parallel sides of a trapezium are 19.8 and 7.2 and its area is 135 cm²..find its height
Virty [35]

Answer:

10cm

Step-by-step explanation:

the formula for an area of a trapezium:

\frac{(a + b) \times h}{2}  = area

where a and b are the parallel sides and h is the height. equating what we have:

\frac{(19.8 + 7.2) \times h}{2}  = 135

simplify the numerator by adding 19.8 and 7.2=27

\frac{27h}{2}  = 135

multiply both sides by 2

27h = 270

divide both sides by 27

h =  \frac{270}{27}  = 10

the height is 10cm

6 0
3 years ago
If a 36-inch yardstick casts a 21-foot shadow, how tall is a building whose shadow is 168 feet?
MAVERICK [17]
The building would have to be 24 feet tall

36 inch is 3 ft
21/3=7
168/7=24
6 0
3 years ago
How much greater is 4/9 than 2/9. Please answer.
kodGreya [7K]

Step-by-step explanation:

A better way to word this is how much more is 4/9 than 2/9 which is 2/9 more because 2/9 plus 2/9 is 4/9 and the denominator stays the same

4 0
3 years ago
Which of the following states the conditions that the graph meets?
Viktor [21]

Answer:

x ≤ 3

Step-by-step explanation:

The vertical line at x = 3 is solid and shaded to the left

Therefor

x ≤ 3

8 0
3 years ago
Read 2 more answers
Other questions:
  • Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
    8·1 answer
  • Find the degrees for 21 and 22
    9·1 answer
  • The graph below plots the values of y for different values of X:
    14·1 answer
  • Please help asap - will give 20 points
    11·2 answers
  • Complete the problem <br> 5/10 +8/100
    9·2 answers
  • The distance from Philadelphia to Harrisburg is 5 inches on the map. The actual distance is 100 miles. The distance from Allento
    13·1 answer
  • Pls someone pls help me with this question pls
    9·1 answer
  • One month Maya rented 2 movies and 3 video games for a total of $20. The next month she rented 6 movies and 5 video games for a
    7·1 answer
  • What is the reciprocal, multiplicative inverse of -14/15
    9·1 answer
  • Solve for x 5x + 14 &gt;54
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!