What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.

Mathematics

1 answer:

Anna007 [38]3 years ago

5 0

Answer:

$- \frac{5}{2}$

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

$y = \frac{2}{5} x - 4$

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

$= - 1 \div \frac{2}{5}$

$= - 1 \times \frac{5}{2}$

$= - \frac{5}{2}$

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