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sleet_krkn [62]
3 years ago
9

What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

-  \frac{5}{2}

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

y =  \frac{2}{5} x - 4

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

=  - 1 \div  \frac{2}{5}

=  - 1 \times  \frac{5}{2}

=  -  \frac{5}{2}

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