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sleet_krkn [62]
3 years ago
9

What is the slope of a line perpendicular to the line whose equation is 4x−10y=404x−10y=40. Fully simplify your answer.

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

-  \frac{5}{2}

Step-by-step explanation:

4x -10y= 40

Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.

10y= 4x -40

Divide both side by 10:

y =  \frac{2}{5} x - 4

The product of the gradients of perpendicular lines is -1.

⅖(gradient of line)= -1

Gradient of perpendicular line

=  - 1 \div  \frac{2}{5}

=  - 1 \times  \frac{5}{2}

=  -  \frac{5}{2}

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A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
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Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

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f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

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= 0.3 × 0.4

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Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

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3 years ago
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Step-by-step explanation:

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<h2>4</h2>

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