The answer is 6(x^2 -1) I have provided a picture with my work and the answer
Answer: 
Step-by-step explanation:
Given
The radius of the cycle is 
Distance traveled by Paul is 
Distance traveled by one complete revolution of wheel is equivalent to circumference of wheel i.e.
No of revolution made by wheel
The odd numbers between 142 and 156 are these:
143, 145, 147, 149, 151, 153, and 155.
Of these, 143 to the nearest ten is 140.
Likewise, 151 to the nearest ten is 150.
And, 153 to the nearest ten is 150.
Of the seven original numbers, 143, 151, and 153 round to a nearest ten that
is less than the possible mystery number.
To the nearest hundred, 143 goes to 100; 151 goes to 200, and 153 goes to 200.
Of those three, only two round to a nearest hundred that is bigger than the mystery number.
Answer: 151 and 153 are the mystery numbers.
Answer:
5a + 6b + 7
step-by-step explanation:
16 + 8a -3a + 6a -9: subtract 9 from 16
7 + 8a -3a + 6b Now subtract -3a from 8a
5a + 6b + 7 is the final answer.
<u>Solution-</u>
Triangle congruence can be proved by,
- SAS (Side-Angle-Side)
- SSS (Side-Side-Side)
- ASA (Angle-Side-Angle)
- AAS (Angle-Angle-Side)
- RHS (Right-angle-Hypotenuse-Side)
As one side and one angle are already congruent, so another congruent angle or congruent side will yield two congruent triangle.
Hence, option "A. If A ≅ T, then the triangles would be congruent by ASA." and option "B. If B ≅ P, then the triangles would be congruent by AAS" are correct.
Being all the angles acute does not mean that the triangle will be congruent, because there are infinitely many triangle possible that they all the angles are acute still they are not congruent. So, option C is incorrect.
Being a right angle, along with the right angle, the hypotenuse and one of its side must be congruent, in order to be congruent. So, option D is incorrect.
If BC ≅ PQ, then the triangles would be congruent by SAS not by ASA. So, option E is incorrect.
