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2 years ago

What is 2 divided by 9/10

Mathematics

1 answer:

Phoenix [80]2 years ago

8 0

Answer:

20/9

Step-by-step explanation:

2/(9/10)=(2/1)(10/9)=20/9

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Pls help me with my math

natka813 [3]

Answer:

Step-by-step explanation:

Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.

Right line is defined when x is greater or equal to one x ≥ 1.

Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.

Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)

You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.

4 0

1 year ago

PLEASE HELPP FASSTTTTTT

lisabon 2012 [21]

Answer:

sorry, i dont um, im setting, the acc, up and ,20

3 0

3 years ago

I feel like I am asking so my questions but I dont really care its a Sunday xD

dimulka [17.4K]

You would add like terms so it would be 1x then you add 1 to 7 so you would get 8.. the you divide both sides by 1x and you'd get 8=x

4 0

2 years ago

Read 2 more answers

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

6 (r - 4) + r + 30 - 7r

GrogVix [38]

6r-24+r+30-7r (the we divide the regular numbers on one side and the others on the other side)Like this:
(6r+r-7r)+(-24+30)
(7r-7r)+6
And the final answer is 6

8 0

3 years ago

What is 2 divided by 9/10 ​

What is 2 divided by 9/10