<span>cos 2x + sqrt(2) sinx=1
</span><span>
Note that: cos 2x = cos^2x - sin^2x = (1-sin^2x) - sin^2x = 1 - 2sin^2x.
So, when alternatively written, you have the following equation:
</span>- 2sin^2x + sqrt(2)sinx + 1 = 1
- 2sin^2x + sqrt(2)sinx = 0
Then, let z=sin(x). So you get,
- 2z^2 + sqrt(2)z = 0
z(- 2z + sqrt(2)) = 0
Either z=0, or - 2z + sqrt(2) = 0 ---> z=sqrt(2)/2.
Then, since z=0 or z=sqrt(2)/2, therefore sin(x)=0, or sin(x)=sqrt(2)/2.
Then, for you remains just to list the angles. (Let me know if this is not fair or if you got questions.)
Answer:
9 is the answer, wanna know how?
Step by Step explanation : So you do this and that equals 9.
The x-value of -7 shows up more than once in relation ...
B. X -7 -5 -7 2 Y 34 32 40 34
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When there is more than one y-value for an x-value, the relation is NOT a function.
Is this connections academy ?
Answer:
x+y=87
1.50x+.50y=78.50
Step-by-step explanation:
x-represents hot dogs
y-represents soda
