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3 years ago

8

How does the graph of g(x) = 5x – 3 compare to the graph of f(x) = 5*?

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

Answer:

the graph is shifted down 3 units

Step-by-step explanation:

5x-3

meaning the original graph of 5x going down three units

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The point (1,-1) is on the terminal side of angle theta in standard position what are the values of sine cuisine and tangent of

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$\bf \textit{terminal point }\implies 
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&\uparrow &&\uparrow \\
&x&&y
\end{array}
\\\\\\
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Alice wants to get enough tile to cover the kitchen and bathroom without appliances in them so they can use the extra for repair

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3 years ago

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Need help on HS geometry

monitta

Answer:

See below

Step-by-step explanation:

AB is a midsegment.

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2 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

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3 years ago

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Answer:

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Step-by-step explanation:

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