Answer:
The attachment shows ΔBAC ~ ΔBDA
Step-by-step explanation:
You want segment AB to be part of two similar, but not congruent, triangles. One way to do that is to make AB the hypotenuse of one triangle and the leg of another.
It is convenient to construct these triangles using point M as the arbitrary midpoint of the hypotenuse of the larger triangle. (We don't know the coordinates of M—we just know it is on the perpendicular bisector of AB.) BC is a diameter of circle M, and AD is the altitude of ΔABC.
Answer:
x = ± 10
Step-by-step explanation:
Given
y = x² - 100 ← a difference of squares , that is
y = x² - 10² = (x - 10)(x + 10)
To find the x- intercepts let y = 0 , that is
(x - 10)(x + 10) = 0
Equate each factor to zero and solve for x
x - 10 = 0 ⇒ x = 10
x + 10 = 0 ⇒ x = - 10
Answer:
Step-by-step explanation:
Drop a height directly through the middle of the triangle, intersecting the base at a 90 degree angle. We form two right triangles and can use the Pythagorean theorem to solve for the hypotenuse.
The Pythagorean theorem states that for any right triangle, the following is true:
, where 
and 
are two legs of the triangle and 
is the hypotenuse.
Therefore, we have the following equation (using the graph to measure the length of the two legs):
The other "tilted" side must be the same length. The base of the triangle can be measured using the graph - 10 units.
Therefore, the perimeter is 
Answer:
Its either C or D since you put the same thing for both and they are to the greater exponent
Step-by-step explanation:
