For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
5.83 or E
Step-by-step explanation:
Use Pythagorean theorem. 5^2+3^2=c^2 because the diameter is perpendicular it cuts the chord in half.
25+9=c^2
34=c^2
5.83
Reflexive Property=For all real number X,X=X
A number equals itself
Addition Property=For all real number X,y & Z,. if
X=Y then X+y=y+Z
Subtraction Property=For all real number X,Y And Z if X=y then X-Z=y-Z.
The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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