the answer is the first one
Step-by-step explanation:
h(t) = -5t² + 20t + 18
this is a parabola (the curve an object follows when thrown up into the air and then falling back down).
and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).
33 = -5t² + 20t + 18
15 = -5t² + 20t
-3 = t² - 4t
t² - 4t + 3 = 0
the solution of such a quadratic equation is
t = (-b ±sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = -4
c = 3
t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =
= (4 ±sqrt(4))/2 = (4 ± 2)/2
t1 = (4+2)/2 = 6/2 = 3
t2 = (4-2)/2 = 2/2 = 1
the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).
Answer:
<em>The distance from the point to the line is approximately 3.2 units</em>
Step-by-step explanation:
<u>Distance From a Point to a Line</u>
Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.
If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is

The line is given by the equation:
y=3x. We need to transform it into the specified form.
Subtracting 3x:
y - 3x = 0
Comparing with the general form of the line, we have
a=-3, b=1, c=0
The point (xo,yo) is (-1,7), thus:





The distance from the point to the line is approximately 3.2 units
2.25 hrs = 2hrs + 0.25 hr
2hrs + (15/60)hr
2hrs and 15minutes
Letter D
Answer: B) 400/3 Pi ft^3
Step-by-step explanation:
V=πr2h
3=π·52·16
3≈418.87902
and
400
/3
(3.141593)
=418.87902
so its B