Answer:

if(soldYesterday > soldToday){

salesTrend = -1;

} else if(soldToday > soldYesterday){

salesTrend = 1;

}

Explanation:

The if/else statement is more explicit. The first if condition check if soldYesterday is greater than soldToday, if true, then -1 is assigned to salesTrend.

Else if soldToday is greater than soldYesterday, if true, then 1 is assigned to salesTrend.

**Answer:**

**// here is code in c++ to find the approx value of "e".**

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

f = f *a;

// return the factorial of number

return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

for (int x = 0; x <= n; x++)

{

sum += 1.0/fact(x);

}

// print the approx value of "e"

cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

**Explanation:**

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

**Output:**

**enter n:12**

**Approx Value of e is: 2.71828**

1. Answer is B (D9=<span>A2+B3)

2. </span><span>C. identifies how many cells with data were in the range

3. </span><span>A. ascending (smallest to largest)

</span><span>4. A. the current worksheet </span>

**Answer:**

gives label artwork a professional, polished look.

**Explanation:**