Let x and y be the length and width of the rectangle respectively
2(x+y)=32...(1)
x=2y-5...(2)
From (1),we have
2x+2y=32...(3)
By sub.(2) into (3),we have
2(2y-5)+2y=32
4y-10+2y=32
6y=42
y=7
By sub.y=7 into (2),we have
x=2*7-5
x=14-5
x=9
Length =9m
Width =7m
Answer:
By multiplying the length of one side by the amount of sides there are.
Step-by-step explanation:
If you find one length just find the rest by multiplying.
The correct question is
<span>The length of a rectangle if the length is twice the size of the width increased by 1 is it one of the following answers:
A) l= 2w-1
B) l= 2w+1
C) l= 3w
D) none of the choices given
Let
l--------------> </span>length of a rectangle
w-------------> width of a rectangle
we know that
if the length is twice the size of the width increased by 1
l=2w+1
the answer is the option B) l= 2w+1
20% of 52
Set up a proportion.
20/100 = 52/1
Divide
52*0.2 = 10.40
Final answer: 10.4
Okay so in this question it says to solve f(7). This means to plug in the 7 every where you see an x, so that it looks like this:
Then you'll solve it like a normal equation.
Hope this helped! Let me know if there is anything I need to clarify or explain more in depth!