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Kazeer [188]
2 years ago
5

1. Marie purchased a $49.00 gift for a baby shower. She uses a coupon that offers 20% off. How much will Marie soend on the gift

after the coupon?​
Mathematics
1 answer:
elena55 [62]2 years ago
7 0

Answer:

$39.20

Step-by-step explanation:

Since she purchased a $49 gift and uses a coupon that offers 20% off, multiply the cost by 80% (0.8)

49(0.8)=39.2

Marie will spend $39.20 on the gift after using the coupon.

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Tonya took out a loan to help pay for her house. She borrowed $40,000 for 15 years at a yearly simple interest rate of 5%. How m
OLEGan [10]
I may be wrong but it could be 30,000.
3 0
3 years ago
Read 2 more answers
Which number should each side of the equation 45x=845x=8 be multiplied by to produce the equivalent equation of x = 10?
Scilla [17]
2nd or 3rd option I hope I narrowed it down
3 0
3 years ago
1. Given the image function f(x) = 2x2 + 1.
Rudik [331]

Answer:

  1. 4+1=5

Step-by-step explanation:

over the y axis is square root

8 0
2 years ago
Algebraic Reasoning please help!
stiv31 [10]

Answer:

\left[\begin{array}{ccc}7\\4\\2\end{array}\right]

The answer is a single-column matrix (7,4,2)

Step-by-step explanation:

In such multiplication of matrices, you have to proceed by multiplying each ROW of the first matrix by the COLUMN of the second matrix.  So,

\left[\begin{array}{ccc}3&6&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (3 * 2) + (6 * 0) + (1 * 1) = 6 + 0 + 1 = 7

then...

\left[\begin{array}{ccc}2&4&0\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (2 * 2) + (4 * 0) + (0 * 1) = 4 + 0 + 0 = 4

and

\left[\begin{array}{ccc}0&6&2\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (0 * 2) + (6 * 0) + (2 * 1) = 0 + 0 + 2= 2

I hope it helps.

5 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
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