The points M(-7,2), N(-3,4), O(-5,8)M(−7,2),N(−3,4),O(−5,8), and P(-9,6)P(−9,6) form a quadrilateral. Find the desired slopes an
pochemuha
The slope of line PO and MN is 0.5. And the slope of the line ON and MP is negative 2. Then each length of the quadrilateral is 4.47 units.
<h3>What is a quadrilateral?</h3>
It is a quadrilateral with four sides. The total interior angle is 360 degrees.
The points M(−7,2), N(−3,4), O(−5,8), and P(−9,6) form a quadrilateral.
Then the slope of each line of the quadrilateral will be
The slope of the line PO will be
PO = (8-6)/(-5+9)
PO = 2/4
PO = 0.5
The slope of the line ON will be
ON = (8-4)/(-5+3)
ON = 4/(-2)
ON = -2
The slope of the line MN will be
MN = (4-2)/(-3+7)
MN = 2/4
MN = 0.5
The slope of the line MP will be
MP = (6-2)/(-9+7)
MP = 4/(-2)
MP = -2
Then each length of the quadrilateral will be
The length of PO will be
PO = √[(-9+5)² + (6-8)²]
PO = 4.47
The length of ON will be
ON = √[(-5+3)² + (8-4)²]
ON = 4.47
The length of MN will be
MN = √[(-3+7)² + (4-2)²]
MN = 4.47
The length of MP will be
MP = √[(-9+7)² + (6-2)²]
MP = 4.47
More about the quadrilateral link is given below.
brainly.com/question/13805601
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X^2-8x+16= (x-4)^2 because -4 and -4 add to -8 but multiply to 16. Hope that helped.
A circle would be the answer
Answer:
i believe the answer is x >3
Step-by-step explanation:
pls brainliest me if it was helpful
