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Nady [450]
3 years ago
15

Can someone help me find the equation for this line please

Mathematics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

<h2>y=0.5x+1</h2>

Step-by-step explanation:

First you want to mark 2 points. I chose (-2,0) and (2,2), it does not mater what points you chose. Once you have the two points, you need to find the slope. To calculate the slope can be seen below.

Slope (m) = ΔY/ΔX = 1/2 = 0.5

Once you have the slope, which is 0.5, you fill in this equation.

y = mx + b, where m is the slope and b is the y-intercept.

Now filling in given variables, you get this equation.

y = 0.5x + 1

taurus [48]3 years ago
5 0

Answer:

y=1/2x+1

Step-by-step explanation:

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A= 1/2Bh

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4 years ago
Jeremy swims 5 3/5 kilometers in a 7 day period. He swims the same distance each day. What distance does he swim?
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Since 5 3/5 can be turned into 28/5, then divided by 7/1, you will get 4/5. So Jeremy swims 4/5 of a kilometer each day.
4 0
4 years ago
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Lateral surface area
ivann1987 [24]
The answer is going to be <span>181.121506177483. hope that helped</span>
3 0
3 years ago
WILL MARK BRAINLIEST !!!
iren2701 [21]

Answer:

(-3,3) Hope that this does help!

6 0
3 years ago
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
2 years ago
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