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lorasvet [3.4K]
3 years ago
9

Please help me i have 3 more after this

Mathematics
2 answers:
Gnoma [55]3 years ago
8 0

Answer:

E

Step-by-step explanation:

Hopefully that is the correct answer, I'm in the middle of a quiz so sorry if that is wrong!!

VARVARA [1.3K]3 years ago
4 0
The answer is E I had a test like that
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. Find four consecutive odd integers such that the sum of the first and fourth is 55 greater than the opposite of the third.
Setler79 [48]

Answer:

The four consecutive odd integers = 15, 17, 19, 21

Step-by-step explanation:

Four consecutive odd integers in Mathematics when x is an integer is given as:

x , x + 2 , x + 4, x + 6

Where:.

First integer = x

Second integer = x + 2

Third integer = x + 4

Fourth integer = x + 6

The sum of the first and fourth is 55 greater than the opposite of the third

Hence :

x + x + 6 = -(x + 4) + 55

x + x+6 = (-x - 4) + 55

2x + 6 = -x + 51

Collect like terms

2x + x = 51 - 6

3x = 45

x = 15

Therefore,

First integer = x = 15

Second integer = x + 2 = 15 + 2 = 17

Third integer = x + 4 = 15 + 4 = 19

Fourth integer = x + 6 = 15 + 6 = 21

The four consecutive odd integers = 15, 17, 19, 21

4 0
4 years ago
Write the algebraic expression for layla is n years old in 9 more years she will be 22
Margarita [4]

Answer:

n+9=22

Step-by-step explanation:

I think I’m not sure. *your gonna get 13 because 13 plus nine is 22*

7 0
3 years ago
Read 2 more answers
Teresa has 53 buttons. Teresa wants to make 12 puppets how many more buttons will she need
Svetllana [295]

Answer:41

Step-by-step explanation:

3 0
3 years ago
Complete the equation of the line through (1,4) and (2,2).<br> y=
cupoosta [38]

Answer:

y=-2x+6

Step-by-step explanation:

8 0
3 years ago
Please teach me on how to answer this question. (addmath question)
arsen [322]

We know that \overline{x}=8 so:

\overline{x}=8\\\\\\\dfrac{\sum\limits_{k=1}^7\,x_k}{7}=8\qquad|\cdot7\\\\\\ \boxed{\sum\limits_{k=1}^7\,x_k=56}

We want to calculate:

\sum\limits_{k=1}^7\,\big(2x_k-3\big)^2=\sum\limits_{k=1}^7\,\big(4x_k^2-12x_k+9\big)=\\\\\\=\sum\limits_{k=1}^7\,4x_k^2-\sum\limits_{k=1}^7\,\big12x_k+\sum\limits_{k=1}^7\,9=4\sum\limits_{k=1}^7\,x_k^2-12\sum\limits_{k=1}^7\,x_k+\sum\limits_{k=1}^7\,9=\\\\\\=4\cdot672-12\cdot56+7\cdot9=2688-672+63=\boxed{2079}

5 0
3 years ago
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